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Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    \[A+B=C+D\]. If initially the concentration of A and B are both equal but at equilibrium concentration of D will be twice of that of, A then what will be the equilibrium constant of reaction?

    A)  4/9            

    B)  9/4

    C)  1/9             

    D)  4

    Correct Answer: D

    Solution :

      \[A+B=C+D.\]
    \[x\] \[x\] 0 0 at initial
    \[2x\] \[2x\] (At equilibrium)
    \[{{K}_{c}}=\frac{[C][D]}{[A][B]}=\frac{2x\times 2x}{x\times x}=4\]


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