A) \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}-B{{c}^{2}}\]
B) \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}+B{{c}^{2}}\]
C) \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}-B/{{c}^{2}}\]
D) \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}+B/{{c}^{2}}\]
Correct Answer: C
Solution :
Binding energy of a nucleus containing N neutrons and Z protons is \[B=[N{{M}_{n}}+Z{{M}_{p}}-M(N,Z)]{{c}^{2}}\] \[\Rightarrow \] \[\frac{B}{{{c}^{2}}}=N{{M}_{n}}+Z{{M}_{p}}-M(N,Z)\] \[\Rightarrow \] \[M(N,Z)=N{{M}_{n}}+Z{{M}_{p}}-B/{{c}^{2}}\]You need to login to perform this action.
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