A) \[-6\text{ }J\]
B) \[-608\text{ }J\]
C) \[+304\text{ }J\]
D) \[-304\,J\]
Correct Answer: B
Solution :
Work done\[(W)=-{{P}_{ext}}({{V}_{2}}-{{V}_{1}})\] \[=-3\times (6-4)=-6L-atm\] \[=-6\times 101.32\text{ }J\] (\[\therefore \] 1 L-atm\[=101.32\text{ }J\]) \[=-607.92\approx 608\text{ }J\]You need to login to perform this action.
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