A) \[2500\,\Omega \]as a shunt
B) \[245\,\Omega \]as a shunt
C) \[2550\,\Omega \]in series
D) \[2450\,\Omega \]in series
Correct Answer: D
Solution :
To convert a galvanometer into .voltmeter, high resistance should be connected in series with it. Let R is the resistance connected in series with the galvanometer. Galvanometer current \[{{i}_{g}}=\frac{V}{G+R}\] Or \[R=\frac{V}{{{i}_{g}}}-G\] Given, \[G=50\,\Omega ,\] \[{{i}_{g}}=25\times 4\times {{10}^{-4}}={{10}^{-2}}A,V=25V\] \[\therefore \] \[R=\frac{25}{{{10}^{-2}}}-50=2500-50=2450\text{ }\Omega \]You need to login to perform this action.
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