Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    The angle of projection for which the horizontal range and the maximum height, of a projectile are equal is

    A)  \[45{}^\circ \]

    B)  \[\theta ={{\tan }^{-1}}(4)\]

    C)  \[\theta ={{\tan }^{-1}}(0.25)\]

    D)  none of the above

    Correct Answer: B

    Solution :

    Horizontal range = Maximum height ie, \[\frac{{{u}^{2}}\sin 2\theta }{g}=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] or   \[2\sin \theta \cos \theta =\frac{{{\sin }^{2}}\theta }{2}\] or        \[\tan \theta =4\] or           \[\theta ={{\tan }^{-1}}(4)\]


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