A) \[s{{p}^{3}},\text{ }ds{{p}^{2}},ds{{p}^{2}}\]
B) \[s{{p}^{3}},\text{ }ds{{p}^{2}},\text{ }s{{p}^{3}}\]
C) \[s{{p}^{3}},\text{ }s{{p}^{3}},\text{ }ds{{p}^{2}}\]
D) \[ds{{p}^{2}},\text{ }s{{p}^{3}},\text{ }sp\]
Correct Answer: B
Solution :
(I) In\[Ni{{(CO)}_{4}},\]nickel is\[s{{p}^{3}}-\]hybrid because in it oxidation state of\[Ni\] is zero. So configuration of \[_{28}Ni=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{8}},4{{s}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec