A) three
B) five
C) two
D) four
Correct Answer: B
Solution :
In\[{{[Mn{{({{H}_{2}}O)}_{6}}]}^{2+}},Mn\]is present as\[M{{n}^{2+}}\]or\[Mn\] (II), so its electronic configuration \[=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},3{{d}^{5}}\]You need to login to perform this action.
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