A) 10 J
B) 20 J
C) 30 J
D) 50 J
Correct Answer: B
Solution :
Velocity at the top is\[\sqrt{gr}\]and that at the bottom is\[\sqrt{5gr}\]. Hence, required difference in kinetic energy \[=\frac{1}{2}m[5gr-gr]=2gmr\] \[=2\times 10\times 1\times 1=20J\]You need to login to perform this action.
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