A) 5 MeV
B) 7 MeV
C) 10 MeV
D) 14 MeV
Correct Answer: B
Solution :
He atom has \[2p+2n\] Hence, \[\Delta m=(2\times 1.0078+2\times 1.0087)-4.0026\] \[=0.0304\,amu\] \[\therefore \]energy released\[=0.0304\times 931.5MeV\] \[=28.3MeV\] Binding energy per nucleon\[=\frac{28.3}{4}=7\,MeV\] (approximately)You need to login to perform this action.
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