A) 4, 1
B) 3, 7
C) 8, 1
D) 4, 7
Correct Answer: A
Solution :
\[_{90}T{{h}^{228}}{{\xrightarrow[{}]{{}}}_{83}}B{{i}^{212}}+x_{2}^{4}\alpha +y_{-1}^{0}\beta \] \[228=212+4x\] or \[4x=16\text{ }or\text{ }x=4\] \[90=83+2x-y=83+8-y\text{ }or\text{ }y=1\]You need to login to perform this action.
You will be redirected in
3 sec