A) Free carboxylic acid and its conjugate base are of comparable stability
B) The free carboxylic acid is more stable than its conjugate base
C) The conjugate base of the carboxylic acid is more stable than the free carboxylic acid
D) The conjugate acid of the carboxylic acid is more stable than the free carboxylic acid
Correct Answer: C
Solution :
\[RCOOH+NaHC{{O}_{3}}\rightleftharpoons RCOONa+{{H}_{2}}O\] \[+C{{O}_{2}}\] Or\[RCOOH+HCO_{3}^{-}\rightleftharpoons RCO{{O}^{-}}+{{H}_{2}}O+C{{O}_{2}}\] Conjugate base,\[RCO{{O}^{-}}\]is more stable. That is why equilibrium shirts in the forward direction.You need to login to perform this action.
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