A) \[5.33{}^\circ \]
B) \[4{}^\circ \]
C) \[3{}^\circ \]
D) \[2.6{}^\circ \]
Correct Answer: C
Solution :
For dispersion without deviation \[{{\delta }_{1}}-{{\delta }_{2}}=0,\]i.e., \[{{\delta }_{1}}={{\delta }_{2}}\] \[\therefore \] \[({{\mu }_{1}}-1){{A}_{1}}=({{\mu }_{2}}-1){{A}_{2}}\] Or \[(1.54-1)4{}^\circ =(1.72-1)A{{ & }_{2}}\] \[\therefore \] \[{{A}_{2}}=3{}^\circ \]You need to login to perform this action.
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