A) 75 V
B) 150 V
C) 225 V
D) 300 V
Correct Answer: D
Solution :
Time period of AC \[T=\frac{1}{n}=\frac{1}{50}s\] Time interval\[\Delta t\]for current to decrease from 1 A to zero \[=\frac{T}{4}\] \[\therefore \] \[\Delta t=\frac{T}{4}=\frac{1}{50}\times \frac{1}{4}=\frac{1}{200}s\] Change in current, \[\Delta I=0-1=-1A\] Mean induced emf, \[e=-M\left( \frac{\Delta I}{\Delta t} \right)\] \[=1.5\times \frac{-1}{1/200}=300\,V\]You need to login to perform this action.
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