A) 96500 C
B) \[9.65\times {{10}^{6}}C\]
C) \[4.83\times {{10}^{5}}C\]
D) \[1.93\times {{10}^{5}}C\]
Correct Answer: C
Solution :
\[\underset{1\,mol}{\mathop{MnO_{4}^{-1}}}\,+8{{H}^{+}}+\underset{5\,mole}{\mathop{5{{e}^{-}}}}\,\xrightarrow[{}]{{}}M{{n}^{2+}}+4{{H}_{2}}O\] ie, \[5\text{ }F\] Hence, electricity required \[=5\times 96500\,C\] \[=482500\,C\] \[=4.83\times {{10}^{5}}C\]
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