A) \[+2\]
B) \[+4\]
C) \[+3\]
D) \[+6\]
Correct Answer: B
Solution :
The structure of\[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]is as \[H-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-O-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-OH\] It contains peroxide linkage due to which the oxidation number of these two oxygen atoms will be\[-1\]each. \[2\times (+1)+2x+6\times (-2)+2(-1)=0\] \[2+2x-12-2=0\] or \[2x=12\] \[\therefore \] \[x=+6\]
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