A) \[28\,g\,mo{{l}^{-1}}\]
B) \[30\,g\,mo{{l}^{-1}}\]
C) \[26.80\text{ }g\,mo{{l}^{-1}}\]
D) \[25\,g\,mo{{l}^{-1}}\]
Correct Answer: C
Solution :
\[\because \] \[Z=4\]for fee \[\Rightarrow \] \[M=\frac{d{{a}^{3}}{{N}_{A}}}{Z}\] \[=\frac{2.7\times {{(404\times {{10}^{-10}})}^{3}}\times 6.023\times {{10}^{23}}}{4}\] \[=26.80\text{ }g\text{ }mo{{l}^{-1}}\]
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