A) 6 and 8
B) 8 and 8
C) 6 and 6
D) 8 and 6
Correct Answer: D
Solution :
\[{{n}_{\alpha }}=\frac{A-A}{4}\] \[=\frac{200-168}{4}\] \[=8\] \[{{n}_{\beta }}=2{{n}_{\alpha }}-Z+Z\] \[=2\times 8-90+80=6\]You need to login to perform this action.
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