A) one
B) two
C) five
D) one fifth
Correct Answer: B
Solution :
\[2KMn{{O}_{4}}+{{H}_{2}}O+KI\xrightarrow[{}]{{}}2Mn{{O}_{2}}\] \[+2KOH+KI{{O}_{3}}\] Hence, one mole of\[KI\]reduces two moles of \[KMn{{O}_{4}}\].You need to login to perform this action.
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