(i) \[n=4,Z=l\] |
(ii) \[n=4,l=0\] |
(iii) \[n=3,l=2\] |
(iv) \[n=3,l=1\] |
A) (iv) < (ii) < (iii) < (i)
B) (ii) < (i^) < (i) < (iii)
C) (i) < (iii) < (ii) < (iv)
D) (iii) < (i) < (iv) < (ii)
Correct Answer: A
Solution :
Greater the value of\[n+l,\]more will be the energy of electron. If the two electrons have same value for\[(n+l)\]then one with lower value of n should be filled first because it possesses lower energy. (i) \[n=4,l=1\therefore n+l=4+1=5\] (ii) \[n=4,l=0\therefore n+l=4+0=4\] (iii) \[n=3,l=2\therefore n+l=3+2=5\] (iv) \[n=3,l=1\therefore n+l=3+1=4\] \[\therefore \]The correct order of energy is (iv) < (ii) < (iii) < (i)You need to login to perform this action.
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