A) \[0.353\times {{10}^{-10}}\]
B) \[0.530\times {{10}^{-10}}\]
C) \[1.12\times {{10}^{-10}}\]
D) \[2.12\times {{10}^{-10}}\]
Correct Answer: C
Solution :
\[[A{{g}^{+}}]=1.06\times {{10}^{-5}}g-ion/L\] \[=1.06\times {{10}^{-5}}mol/L=[C{{l}^{-}}]\] \[AgCl(s)A{{g}^{+}}+C{{l}^{-}}\] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]\] \[={{(1.06\times {{10}^{-5}})}^{2}}\] \[=1.12\times {{10}^{-10}}\]You need to login to perform this action.
You will be redirected in
3 sec