A) 20 m
B) 200 m
C) 100 m
D) 2000 m
Correct Answer: B
Solution :
When a wire is pulled it stretches (undergoes strain) upto a certain limit the amount it stretches is proportional to the load divided by the cross-sectional area of the wire. \[Stress=\frac{Force}{Area}=\frac{mg}{A}=\frac{V\rho g}{A}=\frac{LA\rho g}{A}\] \[\therefore \] Stress \[=L\rho g\] Given, stress\[=6\times {{10}^{6}}N{{m}^{-2}}\] \[\rho =3\times {{10}^{3}}kg\text{ }{{m}^{-3}}\] \[g=10m{{s}^{-2}}\] \[L=\frac{stress}{\rho g}\] \[=\frac{6\times {{10}^{6}}}{3\times {{10}^{3}}\times 10}\] \[=2\times {{10}^{2}}=200m\]You need to login to perform this action.
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