A) 0.5 A
B) 1.6 A
C) 0.16 A
D) 1.0 A
Correct Answer: A
Solution :
When a charged capacitor is allowed to discharge through a resistance inductor electrical oscillations of constant amplitude are produced in the circuit. These are called \[L-C\]oscillations. The energy stored in charged capacitor is \[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}L{{i}^{2}}\] where,\[i\]is current in the circuit and V the potential difference. \[\therefore \] \[i=\sqrt{\frac{C}{L}}V\] Given, \[C=1\mu F=1\times {{10}^{-6}}F,\] \[L=10mH=10\times {{10}^{-3}}H\] \[V=50V\] \[\therefore \] \[i=\sqrt{\frac{1\times {{10}^{-6}}}{10\times {{10}^{-3}}}}\times 50=0.5A\]You need to login to perform this action.
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