A) zero
B) increased by \[6479\overset{o}{\mathop{\text{A}}}\,\]
C) decreased by \[589\overset{o}{\mathop{\text{A}}}\,\]
D) increased by \[589\overset{o}{\mathop{\text{A}}}\,\]
Correct Answer: D
Solution :
Let\[\lambda \]be wavelength of monochromatic light incident on slit S, then angular distance between two consecutive fringes, that is the angular fringe width is \[\theta =\frac{\lambda }{d}\] ?(i) where, d is distance between coherent sources. Given, \[\frac{\Delta \theta }{\theta }=\frac{10}{100}\] So, from Eq. (i) \[\frac{\Delta \lambda }{\lambda }=\frac{\Delta \theta }{\theta }=\frac{10}{100}=0.1\] \[\Rightarrow \]\[\Delta \lambda =0.1\times 5890\overset{o}{\mathop{\text{A}}}\,=589\overset{o}{\mathop{\text{A}}}\,\] (increases)You need to login to perform this action.
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