A) \[400\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[300\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[200\text{ }kJ\text{ }mo{{l}^{-1}}\]
D) \[800\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: D
Solution :
\[{{X}_{2}}+{{Y}_{2}}\xrightarrow[{}]{{}}2XY\] \[\Delta H={{(BE)}_{X-X}}+{{(BE)}_{Y-Y}}-2{{(BE)}_{X-Y}}\] If BE of \[(XY)=a\] Then BE of \[(XX)=a\] and BE of \[(Y-Y)=\frac{a}{2}\] \[\Delta {{H}_{f}}=(X-Y)=-200\,kJ\] \[\therefore \]\[-400\] (for 2 moles\[XY\])\[=a+\frac{a}{2}-2a\] \[-400=-\frac{a}{2}\] or \[a=+800\text{ }kJ\]You need to login to perform this action.
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