A) \[3:4\]
B) \[1:2\]
C) \[1:4\]
D) \[1:1\]
Correct Answer: A
Solution :
Number of moles of \[{{C}_{2}}{{H}_{5}}OH=\frac{138}{46}=3\] Number of moles of\[{{H}_{2}}O=\frac{72}{18}=4\] Mole fraction, \[{{x}_{{{C}_{2}}{{H}_{5}}OH}}=\frac{3}{3+4}\] \[=\frac{3}{7}\] Mole fraction, \[{{x}_{{{H}_{2}}O}}=\frac{4}{3+7}=\frac{4}{7}\] \[\frac{{{x}_{{{C}_{2}}{{H}_{5}}OH}}}{{{x}_{{{H}_{2}}O}}}=\frac{3/7}{4/7}=\frac{3}{4}\]You need to login to perform this action.
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