A) 17.35 MeV
B) 18.06 MeV
C) 177.35 MeV
D) 170.35 MeV
Correct Answer: A
Solution :
The total mass of the initial particles \[{{m}_{i}}=1.007825+7.016004\] \[=8.023829u\] and the total mass of final particles \[{{m}_{f}}=2\times 4.002603\] \[=8.005206\text{ }u\] Difference between initial and final mass of particles \[\Delta m={{m}_{i}}-{{m}_{f}}\] \[=8.023829-8.005206\] \[=0.018623\text{ }u\] The Q-value is given by \[Q=(\Delta m){{c}^{2}}\] \[=0.018623\times 931.5\] \[=17.35MeV\]You need to login to perform this action.
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