A) 0.24
B) 0.06
C) 0.0036
D) 0.0144
Correct Answer: C
Solution :
\[Ca{{(HC{{O}_{3}})}_{2}}(s)\xrightarrow[{}]{{}}CaO(s)+C{{O}_{2}}(g)+{{H}_{2}}O & (g)\] Total pressure is due to\[C{{O}_{2}}(g)\]one\[{{H}_{2}}O(g)\] molar ratio being equal. Thus, \[{{p}_{C{{O}_{2}}}}={{p}_{{{H}_{2}}O}}\] \[{{p}_{C{{O}_{2}}}}={{p}_{{{H}_{2}}O}}=0.06\,bar\] \[{{k}_{p}}={{p}_{C{{O}_{2}}}}\times {{p}_{{{H}_{2}}O}}\] \[=0.06\times 0.06\] \[=0.0036\]You need to login to perform this action.
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