A) 1.23 V
B) 2.46 V
C) 0.615 V
D) 0.31 V
Correct Answer: A
Solution :
\[2{{H}_{2}}+{{O}_{2}}\xrightarrow[{}]{{}}2{{H}_{2}}O\] Total electrons involved = 4 \[\Delta G{}^\circ =-nFE{}^\circ \] \[-475\times 1000=-4\times 96500\text{ }E{}^\circ \] \[E{}^\circ =1.23V\]You need to login to perform this action.
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