Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    Mass of 2 kg is moving with a string in horizontal circle with angular velocity 5 cycle/m keeping the radius constant, tension in string is doubled. Now, the angular velocity of the mass will be

    A) 14cycles/min

    B) 10cycles/min

    C) 2.25 cycles/min

    D) 7 cycles/min

    Correct Answer: D

    Solution :

    Tension in the string should be equal to centripetal force \[T=\frac{m{{v}^{2}}}{r}\] where, m = mass of body                r = radius of circular path                v = linear velocity of body m and r are constant \[v\propto \sqrt{T}\] \[\frac{{{v}_{2}}}{{{v}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{1/2}}={{\left( \frac{2{{T}_{2}}}{{{T}_{1}}} \right)}^{1/2}}\] \[{{v}_{2}}=\sqrt{2}\,{{v}_{1}}=\sqrt{2}\times 5\]  \[=5\times 14=7\]cycles/min


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