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Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    Henry's law constant for the molality of methane in benzene at 298 K is \[4.27\times {{10}^{5}}\]mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

    A) \[1.78\times {{10}^{-4}}\]                               

    B) \[1.78\times {{10}^{-5}}\]

    C) \[1.78\times {{10}^{-4}}\]                               

    D) \[1.78\times {{10}^{-6}}\]

    Correct Answer: B

    Solution :

    \[{{K}_{H}}=4.27\times {{10}^{5}}\]mm Hg (at 298 K)  \[p=760\,\,mm\] Applying Henry's law, \[p={{K}_{H}}x\]where\[x=\]Mole fraction or solubility of methane. \[x=\frac{p}{{{K}_{H}}}=\frac{(760\,\,mm)}{(4.27\times {{10}^{5}}mm)}\] \[=1.78\times {{10}^{-5}}\]


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