A) \[\frac{100-23}{373}\]
B) \[\frac{100+23}{373}\]
C) \[\frac{100+23}{100}\]
D) \[\frac{100-23}{100}\]
Correct Answer: B
Solution :
Using the relation for efficiency of Carnot's engine \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{373-250}{373}\] \[=\frac{123}{373}=\frac{100+23}{373}\]You need to login to perform this action.
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