A) 20m
B) 18m
C) 16m
D) 25m
Correct Answer: B
Solution :
Acceleration of point \[a=\frac{dv}{dt}=6t+5\] \[\int_{0}^{v}{dv=\int_{0}^{t}{(6t+5)dt}}\] \[v=\frac{6{{t}^{2}}}{2}+5t\] \[\frac{ds}{dt}=\left( \frac{6{{t}^{2}}}{2}+5t \right)\] \[\Rightarrow \] \[ds=(3{{t}^{2}}+5t)dt\] \[s=\frac{3{{t}^{2}}}{3}+\frac{5{{t}^{2}}}{2}\] \[t=2s\] \[s=3\times \frac{{{2}^{3}}}{3}+\frac{5\times {{2}^{2}}}{2}=18\,m\]
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