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Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    In a potentiometer of one metre length an unknown emf voltage source is balanced at 60 cm length of potentiometer wire, while a 3\[3\upsilon \]battery is balanced at 45 cm length. Then, the emf of the unknown voltage source is

    A) 3V                                             

    B) 2.25V

    C)  4V                            

    D) 4.5V

    Correct Answer: C

    Solution :

    Let \[{{l}_{1}}\] and \[{{l}_{2}}\] be the balancing length with the cells \[{{E}_{1}}\] and \[{{E}_{2}}\] respectively, then \[{{E}_{1}}=x{{l}_{1}}\] and \[{{E}_{2}}=x{{l}_{2}}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] \[\frac{{{E}_{1}}}{3}=\frac{60}{35}\] \[{{E}_{1}}=4V\]   


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