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Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    Two pendulums have time periods t and\[5t/4\]. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

    A) 45°                                            

    B)  90°

    C) 60°                                            

    D) 30°

    Correct Answer: B

    Solution :

    Whom bigger pendulum of time period (5t/4) completes one vibration, the smaller pendulum will completes (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase \[t/4\,\,\sec =\frac{\pi }{2}\] rad = 90°.


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