A) 1mol
B) 3mol
C) 1.5mol
D) 2mol
Correct Answer: C
Solution :
\[\underset{2mol}{\mathop{2{{H}_{2}}S}}\,+\underset{1\,mol}{\mathop{S{{O}_{2}}}}\,\to 2{{H}_{2}}O+\underset{3\,mol}{\mathop{3S}}\,\] Given 1 mol 1 mol? Thus, \[{{H}_{2}}S\]is the limiting reactant forming 1.5 mol sulfurYou need to login to perform this action.
You will be redirected in
3 sec