A) When \[{{\chi }_{A}}=1\] and\[{{\chi }_{B}}=0,\] then \[p=p_{A}^{\circ }\]
B) When \[{{\chi }_{B}}=1\] and\[{{\chi }_{A}}=0,\] then \[p=p_{B}^{\circ }\]
C) When \[{{\chi }_{A}}=1\]and\[{{\chi }_{B}}=0,\] then \[p<p_{B}^{\circ }\]
D) When \[{{\chi }_{B}}=1\] and\[{{\chi }_{A}}=0,\] then \[p>p_{A}^{\circ }\]
Correct Answer: A
Solution :
In the graph, when \[{{x}_{A}}=1\] and \[{{x}_{B}}=0\], then \[p=p_{A}^{\circ }\] and when \[{{x}_{B}}=1\]and \[{{x}_{A}}=0\] thus \[p=p_{B}^{\circ }\]You need to login to perform this action.
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