Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    An electric motor runs on DC source of emf 200V and draws a current of 10A. If the efficiency be 40%, then the resistance of armature is

    A) \[2\Omega \]                                       

    B) \[8\Omega \]

    C) \[12\Omega \]                                     

    D) \[10\Omega \]

    Correct Answer: C

    Solution :

    Input power = VI \[=200\times 10\] \[=2000\,W\] Output power \[=\frac{40}{100}\times 2000=800\,W\] Power loss In heating of the armature \[=2000-800=1200\,\,W\]             \[{{l}^{2}}R=1200\]                \[R=\frac{1200}{{{l}^{2}}}\]                    \[=\frac{1200}{10\times 10}\]               \[R=12\Omega \]


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