A) 45°
B) 60°
C) 90°
D) 180°
Correct Answer: A
Solution :
The relation for refractive index of prism is \[\mu =\frac{\sin \,\,i}{\sin \,\,r}\] ? (i) The condition for minimum deviation is \[r=\frac{A}{2}=\frac{{{60}^{\circ }}}{2}={{30}^{\circ }}\] Putting the given value of \[\mu =\sqrt{2}\]and, r = 30° the Eq. (i) we get, \[\sqrt{2}=\frac{\sin \,\,i}{\sin \,{{30}^{\circ }}}\] \[\sin \,i=\sqrt{2}\times \frac{1}{2}=\frac{1}{\sqrt{2}}\] \[\sin \,i=\sin \,{{45}^{\circ }}\] \[i={{45}^{\circ }}\]
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