A) 30 kV
B) 50 kV
C) 80 kV
D) 60 kV
Correct Answer: A
Solution :
From the formula, \[ev=h\frac{c}{\lambda }\] \[v=\frac{hc}{e\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 0.4125\times {{10}^{-10}}}\] \[=30\times {{10}^{3}}V=30\,kV\]
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