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Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    The efficiency of a Carnot engine operating with reservoir temperature of 100°C and -23°C will be

    A) \[\frac{100-23}{373}\]

    B) \[\frac{100+23}{373}\]

    C) \[\frac{100+23}{100}\]                     

    D)  \[\frac{100-23}{100}\]

    Correct Answer: B

    Solution :

     Using the relation for efficiency of Carnot's engine               \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{373-250}{373}\]                  \[=\frac{123}{373}=\frac{100+23}{373}\]


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