A) \[32\times {{10}^{-5}}J,16\times {{10}^{-5}}J\]
B) \[16\times {{10}^{-5}}J,8\times {{10}^{-5}}J\]
C) \[48\times {{10}^{-5}}J,12\times {{10}^{-5}}J\]
D) \[36\times {{10}^{-5}}J,2\times {{10}^{-5}}J\]
Correct Answer: A
Solution :
Potential energy of the film \[=2TA\] \[=2\times 40\times {{10}^{-3}}\times 4\times {{10}^{-3}}\] \[=32\times {{10}^{-5}}J\] Change in potential energy \[=2T\Delta A\] \[=2\times 40\times {{10}^{-3}}[4\times {{10}^{-3}}-2\times {{10}^{-3}}]\] \[=16\times {{10}^{-5}}J\]You need to login to perform this action.
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