Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    The amplitude of an oscillating simple pendulum is 10 cm and its time period is 4s. Its speed after Is when it passes through its equilibrium position is

    A) zero                                         

    B) 2.0 m/s

    C) 0.3m/s                                    

    D) 0.4 m/s

    Correct Answer: A

    Solution :

    \[y=A\,\,\sin \,\omega t\] \[\frac{dy}{dt}=v=A\omega \,\,\cos (\omega t)\] \[=A\times \frac{2\pi }{T}\cos \left( \frac{2\pi }{T}t \right)\] \[=\frac{2\pi \times 0.1}{4}\cos \frac{2\pi \times 1}{4}\] \[=\frac{2\pi \times 0.1}{4}\cos \frac{\pi }{4}=0\]


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