A) \[12\,\pi \]
B) \[8\,\pi \]
C) \[5\,\pi \]
D) \[2\,\pi \]
Correct Answer: C
Solution :
Mutual inductance between two coils \[M=0.005H\] Peak current \[{{l}_{0}}=10\,A\] Angular frequency \[\omega =100\,\pi \]rad/s Current \[l={{l}_{0}}\sin \,\omega \,t\] \[\frac{d}{dt}=\frac{d}{dt}({{l}_{0}}\sin \omega \,t)\] \[={{l}_{0}}\cos \omega \,t.\omega \] \[=10\times 1\times 100\pi \] \[=1000\,\pi \] Hence, induced emf is given by \[E=M\times \frac{di}{dt}\] \[=0.005\times 1000\times \pi =5\pi \,V\]You need to login to perform this action.
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