A) solution turns green due to formation of \[C{{r}^{3+}}\]
B) solution turns blue due to formation of \[Cr{{O}_{5}}\]
C) solution turns orange due to formation of \[C{{r}_{2}}O_{7}^{2-}\]
D) no effect takes place
Correct Answer: C
Solution :
\[C{{O}_{2}}+{{H}_{2}}O\rightleftharpoons {{H}_{2}}C{{O}_{3}}\rightleftharpoons 2{{H}^{+}}\] \[\underset{Yellow}{\mathop{2CrO_{4}^{2-}+2{{H}^{+}}}}\,\to \underset{Orange}{\mathop{{{H}_{2}}O+C{{r}_{2}}O_{4}^{2-}}}\,\]
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