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Manipal Medical Manipal Medical Solved Paper-2014

  • question_answer
    In the following reaction, \[2{{H}_{2}}S+S{{O}_{2}}\to 2{{H}_{2}}O+3S\] 1mol each of \[S{{O}_{2}}\]and \[{{H}_{2}}S\]  will give sulphur

    A) 1mol                                        

    B) 3mol

    C) 1.5mol                     

    D) 2mol

    Correct Answer: C

    Solution :

    \[\underset{2mol}{\mathop{2{{H}_{2}}S}}\,+\underset{1\,mol}{\mathop{S{{O}_{2}}}}\,\to 2{{H}_{2}}O+\underset{3\,mol}{\mathop{3S}}\,\] Given 1 mol 1 mol? Thus, \[{{H}_{2}}S\]is the limiting reactant forming 1.5 mol sulfur


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