A) \[n=3\,to\,n=\]1 states
B) \[n=4\,to\,n=\]3 states
C) \[n=3\,to\,n=\]2 states
D) \[n=2\,to\,n=\]1 states
Correct Answer: B
Solution :
Number of wavelengths\[=\frac{n(n-1)}{2}\]where, n = number of orbit from which transition takes place. \[\therefore \] \[6=\frac{n(n-1)}{2}\] \[n=4\] \[\therefore \]The wavelength of emitted radiations will be maximum for transition n = 4 to n = 3.You need to login to perform this action.
You will be redirected in
3 sec