A) 6 g
B) 9 kg
C) 26 g
D) 29 kg
Correct Answer: B
Solution :
Molecular weight of \[Ca{{C}_{2}}=40+2\times 12=64\] \[\because \] 64 kg of \[Ca{{C}_{2}}\]gives = 24 + 4 = 28 kg of ethane \[\therefore \] 20 kg of \[Ca{{C}_{2}}\]will give \[=\frac{28}{64}\times 20\] \[=\frac{7\times 20}{16}=\frac{35}{4}\] \[=8.75\] \[\approx 9kg\]polytheneYou need to login to perform this action.
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