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Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    A common emitter amplifier is designed with \[n-p-n\]transistor (\[\alpha =0.99\]). The input impedance is\[1\,k\Omega \]. and load is \[10\,k\Omega \]. The voltage gain will be

    A) 9900                         

    B) 99     

    C) 9.9                                            

    D) 990

    Correct Answer: D

    Solution :

    Voltage gain =\[=\beta \times \] resistance gain \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.99}{(1-0.99)}=99\] Resistance gain \[=\frac{10\times {{10}^{3}}}{{{10}^{3}}}=10\] Voltage gain\[=99\times 10=990\]


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