A) 0.153 nm
B) 0.613 nm
C) 1.22 nm
D) 0.302 nm
Correct Answer: A
Solution :
The de-Broglie wavelength associated with voltage is given by \[\lambda =\frac{1.227}{\sqrt{V}}nm\] \[=\frac{1.227}{\sqrt{64}}nm\] \[=0.153\,nm\]
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