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Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    A straight line conductor of length 0.4 m is moved with a speed of 7 \[m{{s}^{-1}}\] perpendicular to magnetic field of intensity of 0.9\[Wb{{m}^{-2}}\]. The induced emf across the conductor is

    A) 25.2 V                                      

    B) 5.24 V

    C) 2.52V                                       

    D) 1.26V

    Correct Answer: C

    Solution :

    The induced emf across the conductor E = Blv \[=0.9\times 0.4\times 7=252\,V\]


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